Calculating the Distance Between Interference Maxima: Yellow Light

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SUMMARY

The discussion focuses on calculating the distance between the first and second interference maxima for yellow light with a wavelength of 589 nm passing through a double slit with a slit separation of 0.5 mm and a slit width of 100 micrometers. The screen is positioned 4 m from the slits. The user seeks clarification on the correct approach to determine the angles theta1 and theta2, which are essential for calculating the distance between the maxima on the screen.

PREREQUISITES
  • Understanding of wave interference principles
  • Familiarity with the double-slit experiment
  • Knowledge of trigonometric functions, specifically tangent
  • Ability to apply the small angle approximation in physics
NEXT STEPS
  • Review the double-slit interference equations, particularly for maxima positions
  • Learn how to derive the angles of interference maxima using the formula sin(theta) = m * (lambda/d)
  • Explore the application of the small angle approximation in interference problems
  • Practice calculating distances between interference maxima in various setups
USEFUL FOR

Students studying optics, physics educators, and anyone interested in understanding wave interference patterns in experiments involving light.

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Homework Statement



a)Yellow light Lambda= 589nm falls on a double slit. The distance between two slits is d=0.5 mm the width of each slit is a=100 micrometer. A screen showing the interference pattern is located 4 m behind the slits.



Homework Equations



What is the distance between the first and the second maximum on the screen ?


The Attempt at a Solution



To calculate the distance

tan theta1 = X1 / L
tan theta2 = X2/ L

X2 - X1 = is the answer ?

Is this right ? If it is , how can i calculate theta1 and theta2 ?
Thanks
 
Physics news on Phys.org
Where your textbook discusses the double slit there should be an equation, either for intensity as a function of angle OR the angles of the maxima (1st, 2nd, etc.)
 

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