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## Homework Statement

My question is at https://imgur.com/a/lDOUzjY . The de Broglie wavelength of the atoms in question is 45 pm. The distance from the slits to the detection plane is 1.95m. Each slit width is 1 micrometer. The distance between the slits is 8 micrometers.

2. Homework Equations

2. Homework Equations

y_{min} = λL/a where λ is the wavelength, L is the distance between the slits and the detection plane, and a is the slit width. This is for a minimum in a diffraction experiment.

## The Attempt at a Solution

The width of the diffraction envelope is 2y=2(λL/a)=175.5 micrometers where y is the distance from the central maximum to the first minimum(either above or below it). My question is about the number of interference fringes that fit in the envelope. Is it the intersection of the two diffraction envelopes of the two slits and not the single slit envelope of the first part?

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