Calculating the force of a kick

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Homework Help Overview

The discussion revolves around calculating the force of a kick in the context of sports safety, specifically regarding the potential for testicular rupture. The original poster is attempting to confirm their calculations and explore the relationship between force and pressure units.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster calculates force using the equation F = MA, applying average kick speed and leg mass. They question the conversion of force to pressure units and whether their calculations are correct. Some participants suggest considering kinetic energy and the distance of impact, while others clarify the distinction between force and pressure units.

Discussion Status

The discussion includes various interpretations of the problem, with some participants questioning the solvability of the original poster's approach. Guidance has been offered regarding the calculation of kinetic energy and the relationship between force and pressure units, but no consensus has been reached on a definitive method.

Contextual Notes

Participants note the need for additional information, such as the distance of foot movement upon impact, to fully resolve the problem. There is also a clarification regarding the difference between pounds as a force unit and psi as a pressure unit.

Oral B
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Homework Statement


I'm writing a paper about wearing jockstraps in sports, and I'm trying to calculate whether the force of an average kick could rupture a testicle (Yeah, it hurts just to even think about). I would like to get the end result in lbs, so I'm using the metric system in the equation and then converting Newtons to lbs. I would just like to confirm that I'm calculating this correctly. As a side note, can this be called psi as well? Like if the end result is 77lbs, would that also mean 77 psi?

Variables:
Average kick speed: 30 m/s (I'm aware that this is the velocity of a kick, but I'm guessing that the average kick will not exceed 30 m/s coming from rest).
Average mass of a leg: 11.5 kgs.
Testicular rupture occurs at ~110lbs of force

Homework Equations


F = MA

The Attempt at a Solution



F = (30)(11.5)
F = 345 Newtons, or ~77lbs.
 
Last edited:
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Troll alert.
 
AJ Bentley said:
Troll alert.

... Why?
 
I don't know that I would say "troll" but the problem you give simply is not solvable. You could use the information you have to find the kinetic energy in the kick and then set "force times distance" equal to that energy but you have two unknowns. You would also need to calculate the distance the foot moves from the time of impact to stopping. That would require information such as the resistance to the kick.
 
HallsofIvy said:
I don't know that I would say "troll" but the problem you give simply is not solvable. You could use the information you have to find the kinetic energy in the kick and then set "force times distance" equal to that energy but you have two unknowns. You would also need to calculate the distance the foot moves from the time of impact to stopping. That would require information such as the resistance to the kick.

Ah alright that makes sense, thank you. I will probably just settle with finding the kinetic energy and go from there, thanks for your help.
 
As a side note, pounds and psi are not the same. A pound is a force unit and psi is shorthand for pounds per square inch, which is a pressure or stess unit. 77 pounds acting on 1 sq in is 77 psi pressure; 77 pounds acting on 2 sq in is 38.5 psi, etc.
 

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