- #1

karabiner98k

- 90

- 12

I'm interested to know how much kilograms force an average car can produce. I made the following calculations to answer my question but I'm not sure if I'm right or wrong!

Imagine we have a 1.8L engine that can produce a max torque of 155 nm @ 4250 RPM.

1st gear ratio = 3.455 Final drive ratio = 4.529 Tire size = 185/65R14 (Rolling Tire Radius = 0.289 meters)

It is a FWD car so we have a drivetrain loss of around 10%.

I calculated the acceleration force as follows:

Wheel torque = 155 x 3.455 x 4.529 = 2425 nm Assuming 10% drivetrain loss, we will end up with

**2183**nm of torque at the wheels.

Now, to calculate acceleration force, I divided 2183 by tire radius (0.289):

2183 / 0.289 = 7553 Newtons of acceleration force.

Finally, to convert Newton to kilograms force:

7553 / 9.8066 =

**770 kgf**

Does it mean that this car can lift 770 kg of weight if its engine and transmission (both as a single unit) are used as an industrial elevator?

Does it mean that this car can lift 770 kg of weight if its engine and transmission (both as a single unit) are used as an industrial elevator?