Car acceleration if resistance forces don't exist

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SUMMARY

The discussion centers on the acceleration of a car with a constant power output of 500 HP in a hypothetical scenario where resistance forces, such as aerodynamic drag and tire friction, are neglected. Participants conclude that while the car can theoretically accelerate from 0-100 km/h and 100-200 km/h in the same time frame of 4 seconds, real-world physics dictates that acceleration decreases with speed due to the relationship between power, thrust, and velocity. The key takeaway is that a car cannot maintain constant acceleration at higher speeds without accounting for resistance forces, which significantly impact performance.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Familiarity with the concepts of power and thrust in automotive engineering
  • Knowledge of kinetic energy calculations, specifically KE = 1/2 mv²
  • Basic principles of vehicle dynamics and resistance forces
NEXT STEPS
  • Explore the relationship between power and thrust in automotive applications
  • Study the effects of aerodynamic drag on vehicle performance
  • Learn about the role of tire friction in vehicle acceleration
  • Investigate the differences between conventional and rocket propulsion systems
USEFUL FOR

Automotive engineers, physics students, and anyone interested in understanding vehicle dynamics and the principles of acceleration in the context of resistance forces.

  • #91
jbriggs444 said:
You showed a 50 N weight on a string pulling a cart. That is a constant force device. It is not a constant power device.
No this not string pulling cart.
Engine/gearbox stay at place and winding wheel lift up weight with rope like cran that has I.C. engine for lifting.Weight is accelerate up.
 
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  • #92
Jurgen M said:
No this not string pulling cart.
Engine/gearbox stay at place and winding wheel lift up weight with rope like cran that has I.C. engine for lifting.Weight is accelerate up.
If you have constant 50 N force, it is a constant force device. Period. End Of Story.

Maybe if it was a 5 kg mass, it could be constant power. But it's not 5 kg. It's labeled as 50 N.
 
  • #93
jbriggs444 said:
If you have constant 50 N force, it is a constant force device. Period. End Of Story.

Maybe if it was a 5 kg mass, it could be constant power. But it's not 5 kg. It's labeled as 50 N.
It has mass of 5kg, on the Earth this aprox 50N, and when accelerate up tension in rope is bigger then 50N...
 
  • #94
PeroK said:
I suspect that he doesn't ride a bicycle!
Indeed bike can travel very fast if reduce aero drag, 183mph (295km/h) !

 
  • #95
phinds said:
A car can't have ANY acceleration if there is no resistance anywhere including the tire/road resistance because the wheels would just spin and the car would go nowhere.

What was it Meatloaf said - you took the words right out of my mouth (the rest doesn't apply here :wink:). Seriously the only reason a car can move is the resistance between the tyres and the road. If there is none all the wheels would do is spin - as you mentioned. I seem to recall Feynman discussing it somewhere in his lectures, which of course anyone interested in applied math/physics should read (but not after a usual course in physics without going into why).

Thanks
Bill
 
  • #96
Jurgen M said:
Problem is that some members at stackechange who comment at special relativity tags, has different comment,answers then here, so it makes even more confusion for me.

With my mentor's hat on first, this is a thread about classical Newtonian mechanics; relativistic considerations are not appropriate. But different answers to the same question can be confusing; so just a passing comment that there are different approaches to relativity that can lead to different ways of explaining things. I think these days the explanation based on the symmetries of an inertial frame gets to the heart of the matter best:
http://www2.physics.umd.edu/~yakovenk/teaching/Lorentz.pdf

If you would like to discuss the matter further please start a thread in the relativity forum.

Thanks
Bill
 

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