- #1

Emre

- 15

- 0

Let's say a car's engine is producing 200 Nm of torque throughout its entire range.since gear ratios and tire radius are fixed,it must provide the same amount of wheel force in a gear.So,theoretically,whatever RPM you launch at,the wheel force should be the same.

But in real world,tire slip becomes too much when we try to launch at high RPM.This is true for any car I have driven so far.Even though the torque at 6000 RPM is lower than torque at 3000 RPM,the car far easily lose traction if we try to launch at 6000 RPM.

Is it so because if we launch at high RPM,the rapid deceleration of flywheel provides extra torque to the crankshaft in addition to torque produced by the engine?I have done some calculations,assuming the flywheel is 28 cm in diameter,ansd has a mass of 10 kg.If we dump the clutch and the RPM rapidly drops from 6000 to 3000,I found that not huge amounts of torque is produced at all.

Is the idea true?Does dumping the clutch at high RPM provides huge amount of extra torque?Is it the reason even low torque cars like s2000 launch really fast?