Calculating the Height of a Cliff Using Rocks

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SUMMARY

The problem involves calculating the height of a cliff using two rocks dropped from its edge under unknown gravitational acceleration. The first rock falls for 13.00 seconds, while the second rock is thrown upwards to a height of 3.000 meters and takes a total of 13.50 seconds to hit the ground. By applying kinematic equations, specifically the equations of motion for uniformly accelerated motion, the height of the cliff can be determined through the relationship between time, initial velocity, and acceleration due to gravity.

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  • Concept of initial velocity and time of flight
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This problem doesn't have a diagram or a picture so:


Suppose you land your spacecraft on a distant planet and disembark extremely close to the top-edge of a cliff. The planet's acceleration due to gravity is unknown and you want to know the height of the cliff. Utilizing your accurate watch you let a rock fall from rest off the cliff edge and note it takes 13.00 seconds to impact the ground below. Next, you throw up a second rock (from the cliff's edge) and it rises to a height of 3.000 meters. The total time (from release to impact) for the second rock to reach the ground is 13.50 seconds. Calculate the height of the cliff.


Thanks for any help!
 
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If it doesn't have a diagram or picture, then make a diagram or picture. You know your initial velocity, and the time it takes to fall to the bottom of the cliff in the first scenario. You don't know height or acceleration.

In the second scenario, you know that at the top of the upward throw, the velocity is going to be 0, and it takes 13.50 seconds to fall 3 + h metres. Again, you don't know the height or the acceleration.

Two equations, two unknowns.
 

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