Calculating the Height of a Trapezium Using Given Side Lengths

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SUMMARY

The discussion centers on calculating the height of a trapezium given the side lengths AB = (x + 3) cm and DC = (2x − 3) cm, with an area of 15 cm². The area formula for a trapezium, A = ½(a + b)h, is utilized to derive an expression for height (h) in terms of x. Participants emphasize the need to rearrange the area formula to isolate h, leading to the conclusion that further algebraic manipulation is necessary to express h explicitly.

PREREQUISITES
  • Understanding of trapezium geometry and properties
  • Familiarity with algebraic manipulation and solving equations
  • Knowledge of area calculation formulas for geometric shapes
  • Basic skills in handling variables and expressions
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  • Study the derivation of the trapezium area formula A = ½(a + b)h
  • Practice isolating variables in algebraic equations
  • Explore examples of height calculations in various trapezium configurations
  • Learn about the implications of variable side lengths on trapezium properties
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Students studying geometry, mathematics educators, and anyone interested in solving geometric problems involving trapeziums and algebraic expressions.

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View attachment 5786

AB = (x + 3) cm, DC = (2x − 3) cm and BE = EC.

area of the trapezium is 15 cm^2 \therefore,(x + 3) (2x − 3) or ? i think you should find the are and use the squarootcan you help me to proceed.
 

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mathlearn said:
AB = (x + 3) cm, DC = (2x − 3) cm and BE = EC.

area of the trapezium is 15 cm^2 \therefore,(x + 3) (2x − 3) or ? i think you should find the are and use the squarootcan you help me to proceed.

Not even close.

The formula for the area of a trapezium is $\displaystyle \begin{align*} A = \frac{1}{2}\,\left( a + b \right) \,h \end{align*}$, where a and b are the parallel sides and h is the height.

Can you get an expression for the height in terms of x?
 

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