MHB Calculating the Height of a Trapezium Using Given Side Lengths

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To calculate the height of the trapezium with bases AB = (x + 3) cm and DC = (2x − 3) cm, the area formula A = 1/2 * (a + b) * h is used, where A is 15 cm². Rearranging the formula allows for the height h to be expressed in terms of x. The next step involves substituting the values of the bases into the area equation to derive an expression for h. This approach will facilitate solving for the height based on the given side lengths. The discussion emphasizes the importance of correctly applying the area formula to find the height.
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AB = (x + 3) cm, DC = (2x − 3) cm and BE = EC.

area of the trapezium is 15 cm^2 \therefore,(x + 3) (2x − 3) or ? i think you should find the are and use the squarootcan you help me to proceed.
 

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mathlearn said:
AB = (x + 3) cm, DC = (2x − 3) cm and BE = EC.

area of the trapezium is 15 cm^2 \therefore,(x + 3) (2x − 3) or ? i think you should find the are and use the squarootcan you help me to proceed.

Not even close.

The formula for the area of a trapezium is $\displaystyle \begin{align*} A = \frac{1}{2}\,\left( a + b \right) \,h \end{align*}$, where a and b are the parallel sides and h is the height.

Can you get an expression for the height in terms of x?
 

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