The discussion centers on calculating the initial speed of an arrow shot horizontally at a target 16 meters away, which impacts 56 centimeters lower than aimed. The key to solving this problem lies in determining the time it takes for the arrow to fall 56 centimeters due to gravity. The relevant kinematic equation, V^2 = Vo^2 + 2aΔx, can be utilized, where 'a' is the acceleration due to gravity and Δx is the vertical displacement.
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catmd13 said:Homework Statement
An archer shoots an arrow horizontally at a target 16m away. The arrow is aimed directly at the center of the target, but it hits 56cm lower. What was the initial speed of the arrow?
Homework Equations
im not sure of an equation because it does not have t.
The Attempt at a Solution
I tried V^2=Vo^2+2adeltax