Calculating the Mass of a Hollow Pipe Using Density and Dimensions

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SUMMARY

The discussion revolves around calculating the mass of a hollow pipe with an outer radius of 4.5 cm, an inner radius of 2.8 cm, and a length of 36 cm, given a density of 7.8 g/cm³. The correct approach involves calculating the volume of the hollow section by subtracting the inner volume from the outer volume. The mass is then determined using the formula mass = density × volume, leading to a final mass of approximately 40 kg after conversion to kilograms. The confusion stemmed from incorrectly adding the inner and outer radii instead of using them separately.

PREREQUISITES
  • Understanding of basic geometry, specifically volume calculations for cylinders.
  • Familiarity with the concept of density and its formula: density = mass/volume.
  • Ability to perform unit conversions, particularly from grams to kilograms.
  • Knowledge of how to manipulate algebraic equations to solve for mass.
NEXT STEPS
  • Study the formula for the volume of a hollow cylinder.
  • Learn about unit conversions between grams and kilograms in detail.
  • Explore density calculations in different materials and their applications.
  • Practice problems involving mass calculations using density and volume for various shapes.
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This discussion is beneficial for students in physics or engineering courses, particularly those focusing on material properties and mass calculations, as well as educators teaching these concepts.

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Homework Statement



A piece of pipe has an outer radius of 4.5cm, an inner radius of 2.8cm and length of 36cm

The density of the pipe is 7.8 g/cm^3

What is the mass of this pipe? Answer is in unites of kg.

Homework Equations



Density=mass/volume

Mass= (density)(volume)

Volume= mass/density

The Attempt at a Solution



I subtracted the volume of the hollow inside of the tube from the large radius (2.8+4.5cm) and multiplied that by the density given. Then I converted to kg by dividing by 1000. My answer came up to be appx 40 kg. But I believe I'm wrong.
 
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movsesinator1 said:
I subtracted the volume of the hollow inside of the tube from the large radius (2.8+4.5cm)...
The outer radius is given as 4.5 cm. (No need to add 2.8+4.5.)
 
Oh yeah thanks.
I thought that i had to add the radii because the diagram on the page made it seem as if the outer radius was that of only the thickness of the pipe.
 

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