The discussion focuses on calculating the normal force acting on a roller coaster car with a mass of 960 kg at two critical points: the top and bottom of a loop with a diameter of 12 m. The normal force at the top of the loop is determined using the equation fn + mg = mv²/r, where both the normal force (fn) and gravitational force (mg) act downward. At the bottom of the loop, the equation fn - mg = mv²/r is applied to find the normal force, indicating that the forces act in opposite directions.
PREREQUISITESThis discussion is beneficial for physics students, mechanical engineers, and anyone interested in the dynamics of roller coasters and circular motion analysis.
tpopono said:A roller coaster car of mass 960 kg starts at a distance of H = 20 above the bottom of a loop 12 m in diameter. If the friction in negligible, find the normal force of the rails on the car when i it is a) pside down the top of the loop and b) at the bottom of hte loop
i have no idea how to do it, thank you