The discussion centers on calculating the normal force exerted on an inclined flat plate struck by a jet of water traveling at 50 m/s. The plate is inclined at 30 degrees to the jet, leading to confusion about the angle's reference point. The correct interpretation is that the angle of 30 degrees refers to the jet's path, making the angle normal to the plate 60 degrees. The formula used for calculating the force is ρ(A)(v²)cos(θ), where θ is the angle of the velocity vector normal to the plate.
PREREQUISITESStudents and professionals in engineering, particularly those focusing on fluid mechanics, as well as anyone involved in designing systems that utilize fluid jets for force application.
It doesn't matter. It is only asking about the force resulting from the deflection of the stream of water. Which way gravity acts is of no consequence.foo9008 said:
My ans would be different, the formula given is rho(A)(v^2)cos theta , where theta is the velocity normal to the plate , if the angle 30 is from horizontal axis, then my theta would be 60, am I right??haruspex said:
Oh, you only meant vertical and horizontal with respect to the way you drew the diagram.foo9008 said:
So my idea that theta=60 is correct?haruspex said:
As in your second attachment, yes.foo9008 said:
![DSC_0596[1].JPG](/data/attachments/81/81740-5075c480004c1695a24a7440c90b5887.jpg?hash=UHXEgABMFp)
