# Force exerted normal to the plate

1. Apr 12, 2016

### foo9008

1. The problem statement, all variables and given/known data
A jet of water , 50mm diameter , with a velocity of 18m/s , strikes a flat plate inclined at 25 degree to the axis of jet as shown in figure, Determine the normal force , P exerted on the plate when plate is stationary .

2. Relevant equations

3. The attempt at a solution

in the diagram attached , i found that the angle between the water velocity make an angle of 65 degree to the normal of the plate ,
so my ans is F = ρA(v)(v cos theta) = 1000(pi)( [(50x10^-3) / 2 ] ^2 ) (18^2)(cos 65) = 278.7 N , is my working correct ? i dont have the ans

#### Attached Files:

• ###### l4.png
File size:
80.1 KB
Views:
83
Last edited: Apr 12, 2016
2. Apr 12, 2016

### haruspex

Your algebraic expression looks right but I don't get same answer (about 4% less). Check your arithmetic.

3. Apr 12, 2016

### foo9008

my ans is 268.8N

4. Apr 12, 2016

### haruspex

That is what I get.