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Calculating the Number of loops in the solenoid

  1. May 16, 2012 #1
    1. The problem statement, all variables and given/known data

    The mathematical formula that connects the magnetic field in a solenoid with the current is given by B=((μ0 x n)/(2πr)) i

    where μ0 = 4∏ x 10^-7 NA^-2 is the 'magnetic constant', n is the number of turns or loops of wire (unknown), r is the radius of the solenoid (0.023m), and i is the solenoid current.

    Use the slop of your line to approximate the number of turns or loops in the solenoid.

    the equation of the line is: y=0.0054x + 0.0004

    Solenoid Current Values:
    1. 3.0A
    2. 2.5A
    3. 2.0A
    4. 1.5A
    5. 1.0A
    6. 0.8A

    B Values (numbers match up with Solenoid Current)
    1. 1.60 x 10^-2
    2. 1.40 x 10^-2
    3. 1.20 x 10^-2
    4. 0.85 x 10^-2
    5. 0.58 x 10^-2
    6. 0.43 x 10^-2

    URGENTLY NEED HELP!!! PLEEEAASSEE!!
     
  2. jcsd
  3. May 16, 2012 #2
    You equation for your B field inside your solenoid does not seem correct.
    The field inside a solenoid is constant and does not depend on the radius.
    [itex] B= \mu_0 n I [/itex] where n is turns per length. unless you are talking about a toroid.
    And also how would you figure out the slope of the line.
     
    Last edited: May 16, 2012
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