Calculating the number of turns and thickness of an electromagnet

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SUMMARY

This discussion focuses on calculating the number of turns and wire thickness for a homemade electromagnet intended for use in a racecar. The user specifies a wire diameter of 0.114 mm (approximately 38 Ga) and dimensions for the electromagnet of 7 mm height, 12 mm width, and 57 mm length. Key calculations include determining the number of turns that fit within the coil dimensions, estimating wire length and resistance, and calculating the required voltage to achieve a current of 0.7 amps. The user is advised to select a thicker wire gauge, such as 22 or 24 Ga, to safely carry the current.

PREREQUISITES
  • Understanding of electromagnetism principles, specifically the relationship between current, turns, and magnetic field strength.
  • Familiarity with wire gauge standards, particularly American Wire Gauge (AWG) measurements.
  • Basic knowledge of electrical resistance calculations and Ohm's Law.
  • Ability to interpret engineering sketches and dimensions for coil design.
NEXT STEPS
  • Calculate the number of turns for a coil using the formula NI = B/H, where B is the magnetic field strength and H is the height of the coil.
  • Research the properties of different wire gauges and their current-carrying capacities.
  • Learn how to calculate wire resistance using the formula R = ρ(L/A), where ρ is resistivity, L is length, and A is cross-sectional area.
  • Explore the use of simulation tools for electromagnet design to visualize and optimize coil configurations.
USEFUL FOR

This discussion is beneficial for hobbyists, engineers, and students interested in electromagnet design, particularly those working on projects involving custom electromagnets for automotive applications.

anru
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I'm working on a homemade electromagnet, to use on my racecar :biggrin:
I want to calculate the number of turns of an electromagnet and the thickness of the wire.

But i have tried to search arround in books, and can't really find any thing.

I know my wire is 0,114mm and dimensions for electromagnet is

height: 7mm
width: 12mm
lenght: 57mm

The form is like a horseshoe, but with 90* edge. Picture is linked:

http://oi47.tinypic.com/15zqlv8.jpg

My material of the core is steel (ignore the fact about type of steel)

I have 0,7 ampere for use.
 
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Please review the equations for the magnetic field strength B in the attachment. In particular, understand the derivation of equation (6).The important parameter of the coil is NI, the product of amps times turns.
Please review the copper wire gauge table at http://www.powerstream.com/Wire_Size.htm
Your wire diameter (0.114 mm) is roughly 38 Ga. However, you will need 22 or 24 Ga. copper to carry 0.7 amps.
 

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i want to calculate number of turns
 
Make an engineering sketch of your electromagnet including coil dimensions. Select the proper copper wire gauge from the copper wire table. Using the wire diameter, calculate the number of turns you can fit into the space for the coils. Using the calculated length of the wire, calculate the wire resistance and the voltage needed to get 0.7 amps. Now calculate the amp turns. Using equation (6) in my earlier post, is the magnet strong enough?
 
The G stands for Gauge or what?
 
The first column in the wire gauge table is the wire gauge (Ga.) number. The third column is the wire diameter in mm. The fifth column is the ohms per 1000 meters. Use column 7 for the maximum amps in a coil.
 
This is my data
37 0.0045 0.1143 523.1 1715 0.17 0.0289 1350 kHz

And what should i do then?

The one with AWG 37
 
So your wire selection is 37 Ga.?

1) How many turns can you fit into the allowed dimensioned space for your coil?
2) What is the estimated wire length?
3) What is the estimated wire resistance?
4) Using the recommended maximum wire current 0f 0.03 amps, calculate the the required voltage.
5) Calculate the amp-turns of the coil.
6) Using equation (6). calculate the B field.
 
thanks bob :-)
 

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