Calculating the Orbital Speed of Mars: An Easy Guide

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SUMMARY

The orbital speed of Mars is calculated using the formula 2 * π * r / Period, where r is the distance from Mars to the Sun, approximately 230 million km, and the orbital period is about 687 days. The calculations yield an orbital speed of approximately 54,779.83 mph when converting from km/h. Understanding this calculation does not require advanced concepts like Kepler's laws, as the basic formula suffices for determining speed. This discussion emphasizes the straightforward nature of the calculations involved in determining Mars' orbital speed.

PREREQUISITES
  • Understanding of basic geometry, specifically circumference calculation
  • Familiarity with the concept of orbital periods
  • Knowledge of unit conversion between kilometers per hour and miles per hour
  • Basic grasp of planetary distances in the solar system
NEXT STEPS
  • Research the application of Kepler's laws of planetary motion
  • Learn about centripetal acceleration and its relation to orbital speed
  • Explore the mathematical derivation of orbital mechanics
  • Investigate the methods used for spacecraft trajectory calculations
USEFUL FOR

Astronomy enthusiasts, physics students, aerospace engineers, and anyone interested in planetary motion and orbital mechanics will benefit from this discussion.

rsyodoom2005
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orbital speed of mars! help!?

Mars is 230 million km from the sun. It completes one orbit in a period of approximately 687 days. Calculate the orbital speed of Mars in mph.

OK so gave me the formula which 2*pi*r/ Period r= distance from the planet to the sun. and cirmumference = 2*pi* r


So i set it up 2*3.1416* 150E6 km /16488 hours (mars hours)

= 57161.57 km/hr then convert to mph 57161.57km hour/1.60km =35725.98 mph
 
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rsyodoom2005 said:
Mars is 230 million km from the sun. It completes one orbit in a period of approximately 687 days. Calculate the orbital speed of Mars in mph.

OK so gave me the formula which 2*pi*r/ Period r= distance from the planet to the sun.

I really don't get what you mean by this. what is equal to what? Nor do I understand
any of the rest of the calculations.

You could use that the centripetal acceleration of a planet is proportional to v^2/r
and the acceleration due to gravity is proportional to 1/r^2 and equal to the centripetal
acceleration.

since for the Earth c_1 * v^2/r = c_2 /r^2 this must also be valid for Mars with the same constants.
 
In order to send a spacecraft to the planet Mars you will need to complete some basic orbital equations using Kepler's law of orbits. In the next few Mars Math Questions, we will look at ways engineers calculate this by introducing you to some basic equations and formulas.

. Mars is 230 million km from the sun. It completes one orbit in a period of approximately 687 days. Calculate the orbital speed of Mars in mph.

The equation to determine orbital speed is 2*Pi*r/Period. r = Distance from the planet to the sun. Circumference = 2*Pi*r

So i set it up 2*3.1416* 230E6 km /16488 hours (mars hours) = 87647.74 km/hour

now to convert mph i divided by the conversion factor of 1.60 which gave me 54779.83 mph (orbital speed of mars)??
 
Oh I see, you get both the period and the radius, so you don't need Keplers laws or acceleration and gravity, but you can just use circumference/period to get the orbital speed.
Your calculation is now correct.
 


rsyodoom2005

I'd advise you to attempt the WAS math problems on your own. This can be considered cheating.
 


Not only is it cheating, but its a very easy problem. They give you the formulas... all you need to do is plug the numbers in...
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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