Calculating the potential energy of a spring

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SUMMARY

The discussion focuses on calculating the potential energy of a spring using the formula Ee = 0.5kx². A force of 18 N compresses the spring by 15 cm, leading to confusion regarding the application of Hooke's Law and the distinction between force and spring constant. The correct approach involves recognizing that the spring constant (k) is not the applied force but a ratio of force to compression distance. The accurate calculation of potential energy results in 1.4 J, contrasting with the incorrect initial answer of 0.2 J.

PREREQUISITES
  • Understanding of Hooke's Law and its application in spring mechanics
  • Familiarity with the formula for potential energy in springs: Ee = 0.5kx²
  • Knowledge of the concepts of force (N) and spring constant (k)
  • Basic algebra skills for manipulating equations
NEXT STEPS
  • Study the derivation and applications of Hooke's Law in various spring systems
  • Learn how to calculate spring constants for different types of springs
  • Explore energy conservation principles in mechanical systems involving springs
  • Investigate real-world applications of spring potential energy in engineering and physics
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Students studying physics, particularly those focusing on mechanics and energy, as well as educators teaching spring dynamics and potential energy concepts.

bobsmith76
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Homework Statement



A force of 18 N compresses a spring by 15 cm. By how much does the spring’s potential energy change?


Homework Equations



Ee = .5kx2

The Attempt at a Solution



Why doesn't .5 * 18 * .152p/sup] do it? Seems pretty obvious. My answer is .2 J, the book's answer is 1.4J
 
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Actually,the k in your equation is not the force applied on the spring,it is a spring constant(force/compressed length).If you insist on using force(18N) to calculate,you can rewrite your equation to 0.5Fx^2 by Hooke's Law(F=kx).Then you should get your answer
 
Ok, but I find distinguishing those two to be rather hard.
 
I think F=kx (Hooke's Law) is a great way to distinguish these 2 variables,I don't know whether it works on you,but that's my way^^(P.S It is always easier to distinguish similar variable by understanding the underlying principle of the equations)
Hope this helps
 
Last edited:
But I don't understand the difference between force compressed and force Newtons.

To me they both measure the same thing. They both measure the force needed to compress a spring.
 
That k is not force compressed,it is a quantity called spring constant or force constant.i think you really don't understand what Hooke law means.Here is the meaning,Hooke's Law states that the tension of the spring is proportional to is extension or compression from its natural length.That k is a proportionality constant which means how many Newton is needed to compress or extend 1 meter of the spring.
 
when talking about springs, k is the spring constant. The spring constant of some spring is a ratio of Force required to compress or stretch it some distance x.

Or: k = \frac{F}{x}

The potential energy of a spring is given in terms of its spring constant times the square of the distance compressed or stretched, like you've got it

E = \frac{1}{2}kx2

so plug and chug



so remember: k = spring constant = N/m

while: F = force = N

that's the difference
 

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