Calculating the potential energy of a spring

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Homework Help Overview

The discussion revolves around calculating the potential energy change of a spring when compressed by a specific force and distance. The subject area includes concepts from mechanics, specifically relating to springs and potential energy.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the relationship between force, spring constant, and potential energy, questioning the correct application of the formula for potential energy in springs. Some express confusion regarding the distinction between force and spring constant.

Discussion Status

The discussion is active, with participants offering clarifications about the definitions of variables involved in the equations. There is an exploration of different interpretations of the problem, particularly regarding the use of force versus spring constant in calculations.

Contextual Notes

Participants highlight the challenge of distinguishing between the force applied to compress a spring and the spring constant, indicating a potential gap in understanding the underlying principles of Hooke's Law.

bobsmith76
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Homework Statement



A force of 18 N compresses a spring by 15 cm. By how much does the spring’s potential energy change?


Homework Equations



Ee = .5kx2

The Attempt at a Solution



Why doesn't .5 * 18 * .152p/sup] do it? Seems pretty obvious. My answer is .2 J, the book's answer is 1.4J
 
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Actually,the k in your equation is not the force applied on the spring,it is a spring constant(force/compressed length).If you insist on using force(18N) to calculate,you can rewrite your equation to 0.5Fx^2 by Hooke's Law(F=kx).Then you should get your answer
 
Ok, but I find distinguishing those two to be rather hard.
 
I think F=kx (Hooke's Law) is a great way to distinguish these 2 variables,I don't know whether it works on you,but that's my way^^(P.S It is always easier to distinguish similar variable by understanding the underlying principle of the equations)
Hope this helps
 
Last edited:
But I don't understand the difference between force compressed and force Newtons.

To me they both measure the same thing. They both measure the force needed to compress a spring.
 
That k is not force compressed,it is a quantity called spring constant or force constant.i think you really don't understand what Hooke law means.Here is the meaning,Hooke's Law states that the tension of the spring is proportional to is extension or compression from its natural length.That k is a proportionality constant which means how many Newton is needed to compress or extend 1 meter of the spring.
 
when talking about springs, k is the spring constant. The spring constant of some spring is a ratio of Force required to compress or stretch it some distance x.

Or: k = [itex]\frac{F}{x}[/itex]

The potential energy of a spring is given in terms of its spring constant times the square of the distance compressed or stretched, like you've got it

E = [itex]\frac{1}{2}[/itex]kx2

so plug and chug



so remember: k = spring constant = N/m

while: F = force = N

that's the difference
 

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