Calculating the Radius of a Circle for Masses Attached by a Cord

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SUMMARY

The problem involves calculating the radius of a circular path for a mass (m1 = 2 kg) moving on a frictionless table, while a second mass (m2 = 4 kg) hangs vertically. The speed of m1 is given as 3.5 m/s, and the system is in equilibrium with m2 remaining at rest. The relevant equations include T = mv²/r for m1 and Mg - t = Mv²/r for m2. The solution requires correctly applying these equations to find the radius.

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Homework Statement



A block of mass m1=2kg is attached to a cord. The cord goes down through a hole in the table and is attached to mass m2=4 kg hanging below the table. The 2 kg mass moves on the table in a circle at a speed of 3.5 m/s the table top is friction less and there is no friction between the cord and the side of the hole. What is the radius of the circle if the 4 kg mass remains at rest?

Homework Equations



Sum of force x direction m1: T=mv^2/r

Sum of forces y direction m1: N-mg=mv^2/r

Sum of forces x direction m2: Mg-t= Mv^2/r

The Attempt at a Solution



I have tried to use this equations and i cannot come up wit the solution. Do i have my equation correctly in this problem?
 
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I guess you use orbital length to get the answer :P
 
Last edited:

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