Calculating the Total Mass on a Surface Bounded by a Triangle

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SUMMARY

The discussion focuses on calculating the total mass of a surface defined by the plane equation 2x - y + z = 3, above a triangular region in the xy-plane bounded by y = 0, x = 1, and y = x. The density function is given by ρ(x,y,z) = xy + z. The correct approach involves setting up a double integral with limits 0 ≤ x ≤ 1 and 0 ≤ y ≤ 2x - 3, and expressing z in terms of x and y. The final integral should include the differential area element dx dy for accurate computation.

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Homework Statement


Let the surface S be the part of the plane 2x-y+z=3 that lies above the triangle in the xy plane that is bounded by the lines y=0, x=1 and y=x. Find the total mass of S if its density (mass per unit area) is given by

ρ(x,y,z)= xy+z


Homework Equations





The Attempt at a Solution



Ok so i know this is a double integral. the limite will be
0≤x≤1
0≤y≤2x-3

and f'(x)= 2, f'(y)= -1

√(f'(x) + f'(y) + 1)= √6

so my equation is

√6∫∫(xy+z)

and i have a feeling I am meant to convert this into polar coordinates but how do you convert the limits to polar coordinates?
 
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You don't need any polar coordinates here. You simply need to express z via x and y in the integral you have got so far. And by the way, it is a mistake not to write dxdy in the integral.
 
A volume integral seems to yield an easy result here.
 
thanks heaps guys, i figured it out, and sorry about the late reply
 

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