- #1
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Homework Help Overview
The discussion revolves around calculating the volume of a six-sided box, specifically one with square top and bottom faces and identical side faces. Participants are exploring the geometry involved and the appropriate formulas for volume calculation.
Discussion Character
- Exploratory, Mathematical reasoning, Assumption checking
Approaches and Questions Raised
- Participants are attempting to apply the formula for the volume of a pyramidal frustum, questioning the values used for areas and height. There is discussion about the correctness of the formula and the specific measurements from the diagram.
Discussion Status
Some participants have provided hints and guidance regarding the formula and values to use, while others are verifying their calculations against the expected answer. Multiple interpretations of the problem are being explored, particularly regarding the shape and dimensions of the box.
Contextual Notes
There is mention of a diagram that provides necessary dimensions, but the exact details of the diagram are not included in the discussion. Participants are also navigating potential discrepancies between their calculated volume and the answer provided.
- #2
Axiom17
- 70
- 0
What's your attempt so far? I.e. method and calculations? 
- #3
njama
- 215
- 1
Hint: It is Pyramidal Frustum. Correct me if I am wrong.
- #4
Axiom17
- 70
- 0
njama said:
No that's what I was thinking too
cheers njama on posting the link OK, so thereddevils give that a go now!
- #5
thereddevils
- 436
- 0
Axiom17 said:No that's what I was thinking too
OK, so thereddevils give that a go now!
ok so from the formula for volume of a pyramidal frustum is given by
V=1/3(A1 + A2 + root(A1)(A2))(h)
the height is root(18)
A1=100 , A2=16
i got V=220 cm^3
but the answer given is 312 cm^3.
- #6
rl.bhat
Homework Helper
- 4,432
- 10
According to the diagram h = 6 cm.
- #7
Axiom17
- 70
- 0
Yes the formula is:
V=\frac{1}{3}h \left( A_{1}+A_{2}+\sqrt{A_{1}\times A_{2}} \right)
Where A_{1} is the bottom area, A_{2} is the top area, and h is the height. Refer to your diagram for these values.
If you check that you're using all of the correct values , then you'll get the answer.
V=\frac{1}{3}h \left( A_{1}+A_{2}+\sqrt{A_{1}\times A_{2}} \right)
Where A_{1} is the bottom area, A_{2} is the top area, and h is the height. Refer to your diagram for these values.
If you check that you're using all of the correct values
, then you'll get the answer. Similar threads
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