Calculating Time for a Person Pulling a Lawn Mower

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SUMMARY

The discussion focuses on calculating the time taken for a person to pull a 20kg lawnmower with a force of 25.0N over a distance of 4.50 meters at a 15-degree angle with a friction coefficient of μ=0.100. The work done by the person is calculated as 109J, while the work done by friction is -85.3J. The final solution for the time taken to pull the lawnmower is determined to be 5.89 seconds, utilizing the relationship between power, work, and time.

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  • Concept of friction and its coefficient
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Homework Statement


A person pulls on a 20kg lawnmower with a force of 25.0N and moves the mower 4.50metes. The handle angle is 15* with the horizontal and μ=0.100.
a) Work done by person √ = 109J
B) Work done by friction √ = -85.3J
C) Find the time ?


Homework Equations


P= W/T = W*(constant velocity)

The Attempt at a Solution



I tried to use one of the power equations though I had 2 unknowns (P and T). I have no idea how to go about finding the time.
 
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zaddyzad said:

Homework Statement


A person pulls on a 20kg lawnmower with a force of 25.0N and moves the mower 4.50metes. The handle angle is 15* with the horizontal and μ=0.100.
a) Work done by person √ = 109J
B) Work done by friction √ = -85.3J
C) Find the time ?


Homework Equations


P= W/T = W*(constant velocity)

The Attempt at a Solution



I tried to use one of the power equations though I had 2 unknowns (P and T). I have no idea how to go about finding the time.

What's the net horizontal force on the lawnmower? What then is the motion? Can you think of a suitable kinematic equation to find the time given the distance traveled?
 
Thank you very much for the help :D. Got it 5.89s
 

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