Pushing a lawn mower, total force exerted?

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SUMMARY

The discussion centers on calculating the force required to accelerate a 13.0 kg lawn mower from rest to 1.8 m/s in 2.0 seconds, considering a retarding force of -50.5 N. The user initially calculated the acceleration as 0.81 m/s² and derived a force of 10.5 N based on this acceleration. However, confusion arose regarding the addition of the retarding force and the correct application of the force components, particularly the angle of 49.0° in relation to the horizontal. Ultimately, the user resolved their confusion with assistance from another problem.

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Homework Statement


A person pushes a 13.0 kg lawn mower at constant speed with a force of 77.0 N directed along the handle, which is at an angle of θ = 49.0° to the horizontal.

Calculate the force the person must exert on the lawn mower to accelerate it from rest to 1.8 m/s in 2.0 seconds with a retarding force of -50.5 N in the x direction.

Homework Equations


Using LaTeX Code: v^2 = v_0^2 + 2 a \\Delta x I found a = 0.81 m/s^2



The Attempt at a Solution


Using the acceleration of 0.81 m/s^2 times 13 kg I get F = 10.5 N, now I think I'm supposed to add the retarding force, but 61 N isn't correct.
Did I miss something?
Found the retarding force by finding the Fpcos(49) = 50.5 (in the x direction) Fp = 77.0 N.
Beyond that I'm lost. Please help
 
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Nevermind, another problem helped me out, thank you! More will come!
 

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