Calculating Time for an Airplane to Come to Rest Using Classical Mechanics

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Homework Help Overview

The problem involves calculating the time it takes for an airplane to come to rest after landing, given its initial speed and distance traveled during deceleration. The subject area is classical mechanics, specifically focusing on motion with constant acceleration.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the use of various kinematic equations and question the assumptions behind the original poster's calculations. Some suggest using mean velocity to find the time, while others emphasize the need for correct equations for constant acceleration.

Discussion Status

The discussion is active, with participants providing different perspectives on the equations used. Some guidance has been offered regarding the correct application of kinematic formulas, and there is an exploration of the implications of constant acceleration in this context.

Contextual Notes

There appears to be confusion regarding the application of equations and the assumptions about forces acting on the airplane during its deceleration. The original poster's initial calculation is challenged, leading to a broader discussion on the correct approach.

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Homework Statement



An airplane touches down at a speed of 100m/s. It travels 1000 metres along the runway
while deceleration at a constant rate before coming to rest. How long did it take the airplane to come to rest on the runway?

Xi=0m/s Xf=1000m Vix=100m/s

Homework Equations


Xf=Xi+Vixt

The Attempt at a Solution


1000=0+100t
t=10s

Why is the answer 20 s? and why does this formula fail?
 
Last edited:
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It seems that your particle isn't affected by any forces, thus it keeps on moving in the same direction with constant speed.
 
the plane need decelation the speed from 100 m/s to 0 m/s so the mean velocity is 50 m/s then t = 20 s.
 
Your math is correct, but your equation is wrong. I've calculated it and the answer
t=20s is correct. Try revisiting your equations.
 
No, it's not wrong at all. you could use the equation and mean velocity. But if you need to use the standard equation. it will be
Xf = Vi*t + 1/2 a*t^2 (1)
Vf = Vi + a*t (2)
a = (Vf - Vi) /t (3)
Xf = Vi*t + 1/2 (Vf -Vi) * t
Xf = 1/2 (Vf +Vi)*t (4)
Xf = 1000 m , Vi = 100 m/s , Vf = 0 m/s
 
Isn't this just constant acceleration motion? Just use the constant acceleration formulae to find the acceleration first.

Useful formulae:
v2 - vi2 = 2aΔx
v=vi + at
 
yes, you are right.
You can use the simple form of energy conservation
1/2 m vf2 - 1/2 m vi2 = m a Δx
=> v2 - vi2 = 2aΔx
Thanks.
 

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