Calculating time required to pressurize compressed air tank

Click For Summary
SUMMARY

This discussion focuses on calculating the time required to pressurize a 636 cubic feet compressed air tank from 0 psig to 15 psig using a compressed air source of 4.46 cfm at 93 psi. The Ideal Gas Law (PV=nRT) is referenced as the foundational equation for this calculation. The user seeks a definitive equation to determine the time needed for the pressurization process, emphasizing the importance of understanding both the flow rate and pressure conditions of the air supply.

PREREQUISITES
  • Understanding of the Ideal Gas Law (PV=nRT)
  • Knowledge of compressed air flow rates (cfm)
  • Familiarity with pressure units (psig)
  • Basic principles of thermodynamics related to gas behavior
NEXT STEPS
  • Research how to apply the Ideal Gas Law for pressurization calculations
  • Learn about the relationship between flow rate and pressure in compressed air systems
  • Investigate methods for calculating time based on volume and flow rate
  • Explore practical applications of compressed air systems in industrial settings
USEFUL FOR

This discussion is beneficial for engineers, technicians, and hobbyists involved in pneumatic systems, as well as anyone interested in understanding the dynamics of compressed air pressurization.

chris.styles
Messages
1
Reaction score
0
Hello,

I searched as best I could but could not find a direct answer to my question; I've seen similar questions but without the required data to be able to make the calculation. I thought this would be a simple calculation to find but apparently not.

Compressed air source is 4.46cfm @ 93psi - assume this stays constant
Tank volume is 636 cubic feet
Initial tank pressure is 0psig
Final tank pressure is 15psig

I need to calculate the time required to pressurize this 636cf tank from 0psig to 15psig when the supply of compressed air is 4.46cfm @ 93psi.

If anyone could provide me with the equation to make this calculation, I would be grateful.
Cheers
 
Engineering news on Phys.org

Similar threads

  • · Replies 5 ·
Replies
5
Views
3K
Replies
5
Views
2K
  • · Replies 22 ·
Replies
22
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
50
Views
7K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K