Calculating Torque and Current for Quadcopter Rotor Blades

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SUMMARY

The discussion focuses on calculating the torque and current for quadcopter rotor blades, specifically those measuring 10cm in length. Each rotor generates a thrust force of 1N, resulting in a total thrust of 4N for the quadcopter. The calculated torque on each rotor is 8mN·m, and the current drawn from a 10V battery is 2A. Key parameters include air density (1 kg/m³), shaft efficiency (0.95), rotor efficiency (0.8), and rotor speed (6000 RPM).

PREREQUISITES
  • Understanding of basic physics concepts such as force, torque, and power.
  • Familiarity with electrical principles, specifically Ohm's Law (P = IV).
  • Knowledge of rotor dynamics and efficiency calculations.
  • Experience with the actuator disk model in aerodynamics.
NEXT STEPS
  • Study the actuator disk model for calculating rotor power requirements.
  • Learn about torque calculations in rotating systems.
  • Research the impact of rotor efficiency on quadcopter performance.
  • Explore advanced electrical concepts related to battery current draw in motors.
USEFUL FOR

Aerospace engineers, quadcopter designers, and students studying rotor dynamics and electrical systems in UAVs will benefit from this discussion.

Timothy Teo
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Homework Statement


The rotor blades of a quadcopter are 10cm long. Given that the thrust force generated by each rotor is 1N (giving a total of 4N for 4 rotors), calculate the torque () on each rotor, and the current drawn (I) from a 10V battery, given the following:

  1. Density of air, a = 1 kg/m3.
  2. Shaft efficiency, Nsh = Psh/Pe , where Psh & Pe are the shaft power and electrical power, respectively, is 0.95.
  3. Rotor efficiency, N =P/ Pe , where P is the power generated by the rotor, is 0.8.
  4. The rotor blades are rotating at a speed of 6000 RPM.
(Hint: Use that actuator disk model to compute the power required by the rotor)

Ans: 8mN.m , I= 2A

Homework Equations


P = I V
KE = 1/2 mv^2
F = mv

The Attempt at a Solution


F = mv. Found velocity of the air exiting the propeller. Tired to use KE equation to find power but it doesn't match the answe.
 
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Where did you get F = mv ? Mass times velocity is momentum, not force. Can you show calculations that you made in your attempt at the solution?
 

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