Calculating Torque on a Circular Loop in an External Magnetic Field

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SUMMARY

The discussion focuses on calculating the torque exerted on a circular loop carrying a current of 6.1 A in an external magnetic field of 5.5 T, with the angle between the field and the plane of the loop being 42°. The torque is calculated using the formula torque = N * I * A * B * sin(theta), where A is the area of the loop. The area is derived from the radius calculated from the circumference of 110 cm, resulting in a torque of approximately 2.1616 N·m. A clarification regarding the angle theta indicates it should be subtracted from 90° for accurate calculations.

PREREQUISITES
  • Understanding of torque calculations in physics
  • Familiarity with magnetic fields and their effects on current-carrying loops
  • Knowledge of trigonometric functions, specifically sine
  • Ability to calculate the area of a circle using the formula A = πr²
NEXT STEPS
  • Study the derivation and applications of the torque formula in electromagnetic contexts
  • Learn about the effects of varying angles on torque in magnetic fields
  • Explore the relationship between current, magnetic field strength, and torque in different configurations
  • Investigate the implications of torque in practical applications such as electric motors
USEFUL FOR

Students studying electromagnetism, physics educators, and engineers involved in designing electromagnetic devices will benefit from this discussion.

Kris1120
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Homework Statement



A current of 6.1 A is maintained in a single circular loop having a circumference of
110 cm. An external magnetic field of 5.5 T is
directed such that the angle between the field
and the plane of the loop is 42◦.
Determine the magnitude of the torque exerted on the loop by the magnetic forces acting upon it.
Answer in units of N · m.


Homework Equations



torque = N*I*A*B*sin(theta)

A=pi*r^2

C=2*pi*r




The Attempt at a Solution



r=1.1/(2*pi)
= 0.17507 m

A=pi*r^2
=pi*(0.17507 m)^2
=0.096288 m^2

torque = 1 loop * 6.1 A * 0.096288 m^2 * 5.5 T * sin(42)
= 2.1616 N*m
 
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Hi Kris1120,

Kris1120 said:

Homework Statement



A current of 6.1 A is maintained in a single circular loop having a circumference of
110 cm. An external magnetic field of 5.5 T is
directed such that the angle between the field
and the plane of the loop is 42◦.
Determine the magnitude of the torque exerted on the loop by the magnetic forces acting upon it.
Answer in units of N · m.


Homework Equations



torque = N*I*A*B*sin(theta)

I believe you make an error later in applying this equation. What does the theta in this equation represent?
 
Oh I have to subtract theta from 90! Thanks!
 

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