Calculating Total Energy of Vibration for a String

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SUMMARY

The total energy of vibration for a string fixed at both ends, oscillating in its nth characteristic mode, is calculated using the formula (A^2)(n^2)(pi^2)T/4L, where A is the amplitude, T is the tension, and L is the length of the string. For a superposition of normal modes, the total energy is given by (A1^2 + 9A3^2)(pi^2)(T)/4L. The discussion emphasizes the importance of integrating kinetic energy and understanding the relationship between tension and mass density in the context of wave mechanics.

PREREQUISITES
  • Understanding of wave mechanics and harmonic motion
  • Familiarity with the concepts of tension and mass density in strings
  • Knowledge of normal modes and superposition principle
  • Ability to perform calculus, specifically integration and differentiation
NEXT STEPS
  • Study the derivation of wave equations for vibrating strings
  • Learn about the principles of superposition in wave mechanics
  • Explore the concept of kinetic and potential energy in oscillatory systems
  • Investigate the effects of varying tension and mass density on vibration modes
USEFUL FOR

Students studying physics, particularly those focused on wave mechanics, as well as educators and anyone involved in teaching or learning about the dynamics of vibrating strings.

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Homework Statement


a.) Find the total energy of vibration of a string of length L, fixed at both ends, oscillating in its nth characteristic mode with an amplitude A. The tension in the string is T and its total mass is M. (HINT: consider the integrated kinetic energy at the instant when the string is straight so that it has no stored potential energy over and above what it would have when not vibrating at all.)

b.) Calculate the total energy of vibration of the same string is it is vibrating in the following superposition of normal modes:
y(x,t)=A1sin( xpi/L)cos(w1t) + A3sin(3xpi/L)cos(w3t- pi/4)
(You should be able to verify that it is the sum of the energies of the two modes separately.)

Answers:
a.) (A^2)(n^2)(pi^2)T/4L
b.) (A1^2 + 9A3^2)(pi^2)(T)/4L[/B]

Homework Equations


y(x,t)=A1sin( xpi/L)cos(w1t) + A3sin(3xpi/L)cos(w3t- pi/4)
U=1/2 mu (dy/dt)^2 + T/2 (dy/dx)^2[/B]

The Attempt at a Solution


https://ca.answers.yahoo.com/question/index?qid=20141120113724AAqz07h
https://ca.answers.yahoo.com/question/index?qid=20141120113815AANH7NE

Thats my attempt, final answer is off ( i put the answer from textbook at the bottom of the last page), sorry couldn't figure out how to post . Any help would be greatly appreciated!

also i just tried to get rid of the omegas using : w(n)=npi/L (T/mu)^(1/2) where mu=M/L
[/B]
 
Last edited by a moderator:
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Oh sorry forgot to mention I figured out A, I'm only trying to solve part b now!
 

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