Calculating Total Time and Height of a Free-Falling Object

  • Thread starter Thread starter thomasxc
  • Start date Start date
Click For Summary

Homework Help Overview

The discussion revolves around calculating the total time and height of a free-falling object, specifically focusing on a scenario where the object falls 0.48 of the total distance in the last second of its fall. The subject area is kinematics.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss applying constant acceleration equations at different time intervals, questioning how to set up the problem without known distances or velocities. There are attempts to clarify the initial conditions and relationships between time and displacement.

Discussion Status

The discussion is ongoing, with some participants offering guidance on using kinematic equations and suggesting ways to express displacement in terms of time. There is a recognition of confusion among participants regarding the setup of the problem, but no consensus has been reached.

Contextual Notes

Participants note the absence of specific distance values and initial or final velocities, relying instead on acceleration and time variables. There is also mention of the initial velocity being zero.

thomasxc
Messages
140
Reaction score
0

Homework Statement



an object falls .48 of the total distance in the last one second of its fall. determine total time and height from which it was dropped

Homework Equations



I have no idea. The kinematics, possibly?

The Attempt at a Solution


I have no idea where to begin. I've tried guess and check with the kinematic equations, to no avail. Please help.

thanks in advance
 
Physics news on Phys.org
hi thomasxc! :smile:

if the total time is T, apply the standard constant acceleration equations at t = T and t = T - 1 :wink:
 
I'm so rusty at all of this. This is on an intro for my physics class. I am totally lost. I don't have distance, initial or final velocities, only acceleration, T and T-1.
 
thomasxc said:
I don't have distance, initial or final velocities, only acceleration, T and T-1.

you do have the initial velocity, it's zero

you also know that s at time t = T-1 is 0.52 times s at time t = T
 
ok. so for displacement, T-1=(.52)t right?

Im lost as to how to set that up.
 
thomasxc said:
ok. so for displacement, T-1=(.52)t right?

noooo :redface:

get some sleep, read the question, and try again in the morning :zzz:
 
v=d/t, with that you'll have the velocity at t=1s... Does that help?
 
I just worked out your problem and you can use s=ut + (at^2)/2 at t=t and t=t-1.

just write 2 eqns and you'll figure out a way easily.
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 5 ·
Replies
5
Views
4K
Replies
34
Views
3K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 5 ·
Replies
5
Views
3K
Replies
5
Views
4K
  • · Replies 4 ·
Replies
4
Views
2K