How High Was the Object Dropped in This Free Fall Problem?

Click For Summary

Homework Help Overview

The problem involves an object in free fall, specifically determining the total height from which it was dropped after falling the last 30 meters in 1.5 seconds. The context is rooted in kinematics and gravitational motion.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss setting the total height in relation to the last 30 meters and the time taken for that fall. Some suggest using kinematic equations while questioning the initial conditions of the fall.

Discussion Status

Multiple approaches are being explored, with some participants suggesting different methods to calculate the total height. There is an emphasis on breaking the problem into parts and considering initial velocities, but no consensus has been reached on a single method.

Contextual Notes

Participants note the importance of initial conditions, particularly the initial velocity when the object is at a height of 30 meters, which affects the application of kinematic equations.

piknless
Messages
9
Reaction score
0

Homework Statement



A certain object is falling in free fall down a building. The object falls the last 30 meters in 1.5 seconds. What was the total height it was dropped at.

Homework Equations



s=(1/2)(g)t^2

The Attempt at a Solution



I've tried setting the total height to x+30 and solving for x.
 
Physics news on Phys.org
piknless said:

Homework Statement



A certain object is falling in free fall down a building. The object falls the last 30 meters in 1.5 seconds. What was the total height it was dropped at.

Homework Equations



s=(1/2)(g)t^2

The Attempt at a Solution



I've tried setting the total height to x+30 and solving for x.


Actually you can use (1/2)gt² only if the initial velocity is 0. In the last 30m the initial velocity is not 0.

You have 30 = V.t + gt²/2 where V is the velocity in h=30m.

You find V=12.5
So T = 12.5/10 + 1.5 = 2.75s
Now you use gt²/2 and you get 37.81m
 
lemme try

suppose total height is h+30

now let time be t(to cover h distance)
h=1/2 gt2
h+30=1/2g(t+1.5)2(it takes 1.5 sec more)

solve for h and t u should find both
 
piknless said:

Homework Statement



A certain object is falling in free fall down a building. The object falls the last 30 meters in 1.5 seconds. What was the total height it was dropped at.

Homework Equations



s=(1/2)(g)t^2

The Attempt at a Solution



I've tried setting the total height to x+30 and solving for x.

It is best to split this problem into two separate parts. Consider the motion between the top of the building until the ball is at a height of 30m above the ground (first part). Then consider the motion from this 30m height to the ground (second part).

If the total height fallen is H then 30m above the ground, it has traveled (H -30)m. It was dropped with zero initial velocity so for the first part of the motion, we have -(H-30) = -\frac{1}{2}gt^2,\,\, (1) keeping consistent with signs.
Now consider the second part. We want to determine the velocity at a height 30m above the ground. You know the time taken to fall this distance so using one of the kinematic relations you should be able to find this velocity.

Now we have all the information required to find the time taken to travel (H-30)m. This is found using another (different) kinematic relation. Sub this time into eqn (1) and you have your H.
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
2K
Replies
34
Views
3K
  • · Replies 38 ·
2
Replies
38
Views
4K
Replies
7
Views
3K
  • · Replies 12 ·
Replies
12
Views
4K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
Replies
4
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K