Calculating Total Time and Height of a Free-Falling Object

  • Thread starter Thread starter thomasxc
  • Start date Start date
Click For Summary
SUMMARY

The discussion focuses on calculating the total time and height of a free-falling object, given that it falls 0.48 of the total distance in the last second of its fall. Participants suggest using kinematic equations, specifically the constant acceleration equations, to derive the necessary values. The initial velocity is confirmed to be zero, and the relationship between the distances at time T and T-1 is established. The key equations to use are s = ut + (at²)/2 for displacement.

PREREQUISITES
  • Understanding of kinematic equations in physics
  • Knowledge of constant acceleration concepts
  • Familiarity with displacement, velocity, and time relationships
  • Basic algebra skills for equation manipulation
NEXT STEPS
  • Study the derivation and application of kinematic equations for free-fall scenarios
  • Learn how to solve problems involving constant acceleration
  • Explore the concept of displacement in relation to time intervals
  • Practice solving physics problems involving initial velocity and acceleration
USEFUL FOR

Students in introductory physics courses, educators teaching kinematics, and anyone interested in understanding the principles of free-fall motion and displacement calculations.

thomasxc
Messages
140
Reaction score
0

Homework Statement



an object falls .48 of the total distance in the last one second of its fall. determine total time and height from which it was dropped

Homework Equations



I have no idea. The kinematics, possibly?

The Attempt at a Solution


I have no idea where to begin. I've tried guess and check with the kinematic equations, to no avail. Please help.

thanks in advance
 
Physics news on Phys.org
hi thomasxc! :smile:

if the total time is T, apply the standard constant acceleration equations at t = T and t = T - 1 :wink:
 
I'm so rusty at all of this. This is on an intro for my physics class. I am totally lost. I don't have distance, initial or final velocities, only acceleration, T and T-1.
 
thomasxc said:
I don't have distance, initial or final velocities, only acceleration, T and T-1.

you do have the initial velocity, it's zero

you also know that s at time t = T-1 is 0.52 times s at time t = T
 
ok. so for displacement, T-1=(.52)t right?

Im lost as to how to set that up.
 
thomasxc said:
ok. so for displacement, T-1=(.52)t right?

noooo :redface:

get some sleep, read the question, and try again in the morning :zzz:
 
v=d/t, with that you'll have the velocity at t=1s... Does that help?
 
I just worked out your problem and you can use s=ut + (at^2)/2 at t=t and t=t-1.

just write 2 eqns and you'll figure out a way easily.
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 5 ·
Replies
5
Views
1K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 5 ·
Replies
5
Views
4K
Replies
34
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
5
Views
4K
  • · Replies 4 ·
Replies
4
Views
2K