Calculating toxicant concentration

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PedroAndrade
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Hi!

In my lab we're preparing a toxicity bioassay using nitrate (NO3-) as the test toxicant. The tests we're doing are range-finding tests, to help determine the lethal concentration (LC50) for that species with nitrate.

We are following the lead of another work (http://www.sciencedirect.com/science?_ob=ArticleURL&_udi=B6V74-4F02KWG-B&_user=10&_rdoc=1&_fmt=&_orig=search&_sort=d&view=c&_acct=C000050221&_version=1&_urlVersion=0&_userid=10&md5=172b82c36ff657803f003c89ddaca62d") which used sodium nitrate (NaNO3) as the source of nitrate. In that article, the test concentrations used for a similar species range from 5 to 160 mg NO3-N/L. This is where my understanding of chemistry is lacking. I'll try to illustrate my doubts with an example:

If I want to find the LC50 for a solution of 10 mg nitrate/L, what do I calculate exactly?
a) 10 mg of NaNO3
b) 13,71 mg of NaNO3 - corresponding to 10 mg of NO3-
c) 60,71 mg of NaNO3 - corresponding to 10 mg of N

My feeling is that b) is correct, but the notation NO3-N is throwing me off. Can anyone help out with this?
 
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I thought it was b) too, lucky thing I asked a friend who's an environmental microbiologist.

It's c). "NO3-N/l" should be read as 'Nitrate nitrogen per liter". So it's just the amount of nitrogen.
 
Thank you very much alxm! You stopped my day from becoming the new season of 24.:smile: