How Does Rubidium Iodide Electrolyte Affect Pseudocapacitor Energy Density?

[Stanley514]

If we have capacitance of 1840 Farads/gram, how much Wh/kg (energy density) it will be?
How it applies to pseudocapacitors?
http://www.sciencedirect.com/science?_ob=ArticleURL&_udi=B6VP5-4TTMNKC-2&_user=http://www.sciencedirect.com/science?_ob=ArticleURL&_udi=B6VP5-4TTMNKC-2&_user=10&_coverDate=01%2F31%2F2009&_rdoc=1&_fmt=high&_orig=gateway&_origin=gateway&_sort=d&_docanchor=&view=c&_searchStrId=1673900364&_rerunOrigin=google&_acct=C000050221&_version=1&_urlVersion=0&_userid=10&md5=57116301b16e7ac6207cb9abc69ef2f0&searchtype=a

 

[tiny-tim]

Hi Stanley514!

If we have capacitance of 1840 Farads/gram, how much Wh/kg (energy density) it will be?

hmm …

let's check the dimensions of these https://www.physicsforums.com/library.php?do=view_item&itemid=101" …

farad/gm = coulomb/volt.gm = coulomb²/joule.gm (Q²T/M²L²)

energy density = joule/m³ (M/LT²)

… no match ​

 

[Stanley514]

I found an example how to convert Farads to joules:
http://forum.onlineconversion.com/showthread.php?t=12108"
There is reports that activated carbon pseudocapacitors with Rubidium iodide electrolyte
are showing capacitane 2272 Farads/gram on positive electrode.http://www.sciencedirect.com/science?_ob=ArticleURL&_udi=B6VP5-51FXRF0-2&_user=10&_coverDate=01%2F31%2F2011&_rdoc=1&_fmt=high&_orig=gateway&_origin=gateway&_sort=d&_docanchor=&view=c&_searchStrId=1693446781&_rerunOrigin=google&_acct=C000050221&_version=1&_urlVersion=0&_userid=10&md5=cddc2aa92d617fb38643ad5880f00d68&searchtype=a"
If we calculate it with above formula it gives us about 12 Megajoules/kg!
The mention that two electrode system reduces capacitance to only 200+ Farads/gram.Do they need to have two electrodes or only one positive electrode could be used?