Calculating Velocity of Water in a Circular Pipe

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Water flowing at 1 m/s in a circular pipe experiences a velocity increase when the pipe's diameter decreases to four-ninths of its original size. The principle of conservation of mass is applied using the equation A1V1 = A2V2, where A represents the cross-sectional area and V the velocity. The area of a circle can be expressed in terms of its diameter, allowing for the calculation of the new velocity downstream. The discussion emphasizes using the volumetric flow rate to determine the velocity in the narrower section of the pipe. Overall, the approach focuses on the relationship between area and velocity in fluid dynamics.
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Homework Statement


Water is flowing at 1 m/s in a circular pipe. If the diameter of the pipe decreases to four-ninth its former value, what is the velocity fo the water downstream?


Homework Equations



AV=AV

3. The Attempt at a Solution [/b
(Area1)(Velocity1)=(Area2)(Velocity2)
then...
(A1)(1 m/s)=(4/9)A1(V2) ?
or
A1=(4/9)(V2)

Is that right what would u do next??
 
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Rewrite the area in terms of its diameter, and then try again.
 
Indeed, remember the area for a circle? *circular* being the key word =).
 
couldn't you just with what your given calculate the volumetric flow rate then, then apply Q = AV to get the velocity in the second pipe.. that's how I would do it
 
A1V1 = A2V2, since the density is uniform/incompressible.

You could do as you say, but then you'd have the equation:
A1 * (delta L1) / delta t = A2 * (delta L2) / delta t

A1V1 = A2V2 is a better one to use; well more "simple" one.
 
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