Calculating & Visualizing Motion: 2kg Circular Motion

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SUMMARY

A body with a mass of 2kg performs circular motion with a radius of 0.4m and completes 20 revolutions per minute. The angular velocity is calculated as 2π/3 rad/s, the linear velocity is approximately 0.8377 m/s, the centripetal acceleration is 1.754 m/s², and the kinetic energy is 0.701 J. The discussion highlights the need for assistance in visualizing the position, velocity, and acceleration vectors at a specific time (t=0.5s) during the motion.

PREREQUISITES
  • Understanding of circular motion principles
  • Knowledge of angular and linear velocity calculations
  • Familiarity with centripetal acceleration concepts
  • Basic skills in vector representation and diagram drawing
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  • Learn how to draw position and velocity vectors in circular motion
  • Study the relationship between angular velocity and linear velocity
  • Explore the derivation of centripetal acceleration formulas
  • Investigate kinetic energy calculations in rotational systems
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toljin123
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Homework Statement


A body of mass 2kg performs circular motion about a point O. The radius of the circle is 0.4m and the mass completes 20 revolutions per minute.Calculate:

1) the angular veloicty.
2)the linear velocity.
3) the centripetal acceleration,and
4) the kinetic energy
5) Draw a diagram showing the position vector, the velocity vector and acceleration vector at time t=0.5s

Answers for 1-4

1) = 2pi/3
2)(0.4) * (2pi/3) = 0.8377
3)(2pi/3)^2(0.4) = 1.754
4)1/2(2)(0.8377)^2 = 0.701 I have completed 1-4, but i having some trouble doing number 5. Any help would be great :)
 
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toljin123 said:

Homework Statement


A body of mass 2kg performs circular motion about a point O. The radius of the circle is 0.4m and the mass completes 20 revolutions per minute.Calculate:

1) the angular veloicty.
2)the linear velocity.
3) the centripetal acceleration,and
4) the kinetic energy
5) Draw a diagram showing the position vector, the velocity vector and acceleration vector at time t=0.5s

Answers for 1-4

1) = 2pi/3
2)(0.4) * (2pi/3) = 0.8377
3)(2pi/3)^2(0.4) = 1.754
4)1/2(2)(0.8377)^2 = 0.701


I have completed 1-4, but i having some trouble doing number 5. Any help would be great :)

Hi Toljin, welcome to PF !

Draw a circle - is it ready? Place a dot on the circumference, indicating the initial position of the body (we assume it small with respect to the radius), and also its position 0.5 s later.

The position vector is just a vector drawn from the centre of the circle to the body.

What do you know about the velocity vector?
tangent to the circle
The angular velocity is constant, so you get only centripetal acceleration. What is its direction?

ehild
 

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