Calculating Voltage & Velocity of Electrons in an Electron Microscope

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Homework Help Overview

The discussion revolves around calculating the voltage and final velocity of electrons in an electron microscope, specifically focusing on their wavelength and energy relationships.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to use energy equations related to wavelength and kinetic energy to find voltage and velocity. Some participants question the applicability of classical mechanics to the problem, while others suggest considering relativistic effects due to the energy levels involved.

Discussion Status

Participants are exploring different interpretations of the problem, particularly regarding the need for relativistic corrections in the calculations. There is no explicit consensus on the approach to take, but various lines of reasoning are being discussed.

Contextual Notes

There is an ongoing discussion about the assumptions regarding the energy of electrons and whether classical mechanics is sufficient for the calculations at hand.

UrbanXrisis
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electrons in an electron microscope are accelerated form rest to a momentum making their wavelength 0.06 nm.

1. what is the voltage Vo needed for this?

2. What is the final electron velocity?

For 1.

[tex]E=\frac{hc}{\lambda}=\frac{1240eVnm}{0.06 nm}[/tex]
solve for E

For 2.

[tex]E=.5mv^2[/tex]
Solve for v plugging in E from #1 and m=mass of electron

is this the correct thought process?
 
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I think that the correct process for classical mechanic.[/color]
 
i'm not sure I understand what you mean
 
This is just a guess but I think he might mean relativistic corrections. I don't think those are absolutely necessary because the electrons energy would be roughly 20keV which is still quite a bit smaller than it's rest energy.
 
oh, you mean for part 2, i should use [tex]E=\sqrt{(pc)^2+(mc^2)^2}[/tex]?
 

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