Calculating voltage within and outside of a solid sphere

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To calculate the potential difference for a uniformly charged solid sphere, the discussion highlights two main parts. For part (a), the potential difference between infinity and the sphere's surface involves integrating the electric field from the surface to infinity, assuming the field at infinity is negligible. For part (b), the potential difference between the sphere's surface and its center requires understanding the charge distribution and electric field within the sphere, noting that the charge density is constant. The conversation emphasizes the importance of correctly defining the variable of integration and understanding the electric field behavior outside a uniformly charged sphere. Clarification on these concepts is essential for solving the problem accurately.
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Homework Statement


A solid sphere with radius R=12 m has charge Q=3 nC distributed uniformly throughout its volume.
(a) Calculate the potential difference between a location at infinity and a location on the sphere’s surface.
(b) Calculate the potential difference between a location on the sphere’s surface and the location at the sphere’s centre.

Homework Equations


V= ∫ E.R (both vectors)

V= kq1q2/r

The Attempt at a Solution



I'm struggling with understanding this unit in general (first year physics- teacher in high school did not teach electricity) so if I could get some help with this question, it might make the unit in general much clearer for me.

This is what I think:

For part A, I'm integrating between the surface of the sphere and infinity - the force at a distance of infinity is negligible so I'm going to assume 0 for it (prof says it's okay to do so).

so if I'm integrating between infinity and the surface, my integral's upper limit would be ∞ and the lower limit would be R (radius of the sphere).

Since Q is distributed evenly around the volume, I would divide Q by the volume at R; so

R∫k3Q/4πR3? I'm not sure if this is right or let alone whether I'm on the right track.

As for Part B, I would do the same thing but between R and r? Volume would be a factor as the gaussian spheres inside the sphere would have a different amount of charge depending on their volume (as the radius increases) ??
 
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starstruck_ said:
Since Q is distributed evenly around the volume, I would divide Q by the volume at R; so

R∫k3Q/4πR3?
You need to understand what you are effectively calculating there.
Dividing by the volume gives the charge density inside the sphere. This is a constant. Your integral is undefined because you have not specified the variable of integration (the "dx"). It cannot be R because R is a constant.
Anyway, there does not seem to be any value in integrating the charge density within the sphere over a range outside it.

What do you know about the field outside a uniformly charged spherical shell?
 
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