Calculating Wavelength of Photons to Produce 30 keV Electrons

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SUMMARY

The discussion centers on calculating the wavelength of photons required to produce 30 keV electrons through Compton scattering. The relevant equation used is E = hc/λ, where E represents energy, h is Planck's constant, c is the speed of light, and λ is the wavelength. Participants clarify that Compton scattering can indeed impart kinetic energy to electrons, and the initial wavelength of the photon must be determined based on the energy gained by the electron. The confusion regarding the relationship between photon energy and electron mass is addressed, emphasizing the need for precise calculations.

PREREQUISITES
  • Understanding of Compton scattering principles
  • Familiarity with the equation E = hc/λ
  • Knowledge of photon energy calculations
  • Basic concepts of electron kinetic energy
NEXT STEPS
  • Calculate photon energy using E = hc/λ for various wavelengths
  • Explore the implications of Compton scattering on electron dynamics
  • Study the relationship between kinetic energy and velocity of electrons
  • Investigate advanced photon-electron interaction models
USEFUL FOR

Physics students, educators, and researchers interested in quantum mechanics and particle physics, particularly those focusing on photon interactions and energy transfer in Compton scattering.

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Homework Statement


56. What wavelength of photons are needed to produce 30 keV electrons in a compton scattering?


Homework Equations


E=\frac{hc}{\lambda}

The Attempt at a Solution


This question throws me off because I was under the impression that compton scattering didn't produce any electrons, but simply deflected them. It also confuses me because I assume it's asking "What photons will produce electrons with total energy of 30-keV?" However, electrons have that much energy in rest mass alone.

Can anyone interpret this better?
 
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Not sure what compton scattering is, but I'd find the velocity of the electrons from their energy and and then use the de Broglie wavelength formula


\lambda = \frac{h}{mv}
 


With all due respect, your suggestion does not make sense in the context of what we've discussed. We've discussed compton scattering, and have not discussed de Broglie wavelengths.
 


Here is my interpretation:

Assume that you have an electron at rest. An incoming photon Compton scatters off it and the electron acquires a kinetic energy of 30 keV. What is the initial wavelength of the photon?
 
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