Calculating Wing Tip Acceleration and Velocity in a Flapping Fly

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A fly flaps its wings 1000 times per second, accelerating the wing tip from rest to a maximum velocity in 0.0025 seconds, covering 2mm in that time. The average acceleration can be calculated, but the initial approach was incorrect; the correct method involves using physics formulas for motion. The discussion highlights that the fly's wing motion involves continuous acceleration and deceleration, leading to an average acceleration of zero when considering the entire flapping cycle. The formulas provided are useful, but they assume constant acceleration, which does not apply to the fly's wing movement. Understanding these concepts is crucial for accurately calculating wing tip acceleration and velocity.
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A fly falps its wings 1000 times per second. This means that the wing tip is accelerated from rest to a maximum velocity in 0.0025 seconds. If the wing tip travels 2mm in this time:

a) What is the average acceleration of the wing tip?
what i got is i converted 2mm to meters then multiplied that by 0.0025seconds
0.002 x 0.0025 = 8m/s
then i get lost from here i don't even think the first part was right.

b) What is the velocity at a maximum
 
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The fly "flaps" its wings back and forth, right? It moves them up and down and up and down... So, it's accelerating and decelerating its wings all the time, changing the direction that they're moving. Average acceleration, the speeding up and the slowing down all averaged together, is zero.

Don't forget the common physics formulas:
x(t)=x_0+v_0t+\frac{1}{2}at^2
v(t)=v_0+at
2a\Delta x=v^2-v_0\,^2
\Delta x=\frac{1}{2}(V+V_0)t

The fourth problem seems like the formula that you want to use, but it's my understanding that this formula assumes constant acceleration and this isn't the case with your fly.
 


Ohhhh that helps so much thanks alott, can't believe i missed that >.<
 
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