Calculating Work and Force of Air Resistance on a Falling Pinecone

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SUMMARY

The discussion focuses on calculating the work done on a 0.16 kg pinecone by air resistance as it falls 18 m, landing at a speed of 11 m/s. The relevant equations include the work-energy theorem, W=FΔx, and the kinematic equation Vf^2=Vi^2 + 2aΔx. The participant initially miscalculated the initial velocity as 18.78 m/s, which is incorrect due to air resistance. The correct approach involves using energy balance to equate potential and kinetic energy, factoring in work done against air resistance.

PREREQUISITES
  • Understanding of Newton's second law (ƩF=ma)
  • Familiarity with kinematic equations (Vf^2=Vi^2 + 2aΔx)
  • Knowledge of the work-energy theorem (W=FΔx)
  • Basic concepts of potential and kinetic energy
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  • Learn how to apply energy balance in mechanics problems
  • Explore the effects of air resistance on falling objects
  • Practice solving problems involving forces and motion in physics
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Homework Statement



A 0.16 kg pinecone falls 18 m to the ground where it lands with a speed of 11 m/s.

a)How much work was done on the pinecone by air resistance?

b)What was the average for of air resistance exerted on the pine cone?

Homework Equations



ƩF=ma

Vf^2=Vi^2 + 2aΔx

W=FΔx=maΔx=1/2(mVf^2)-1/2(mVi^2)

The Attempt at a Solution



I tried using the kinematic equation to find initial velocity while setting the acceleration as gravity. I got 18.78 m/s but that doesn't seem right. I tried using that initial velocity in the work-kinetic energy theorem and it came out to -28.275. However that was the wrong answer. I don't understand where to start with this problem let alone part B. Someone help me please.
 
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The 18.78 m/sec represents the speed if there were no wind resistance. Note that it is larger than what was presented in the problem statement.

Write an energy balance such as:

PE(1) + KE(1) = PE(2) + KE(2) + Work
 
The net work done is equivalent to the work by gravity minus the work by friction.

EDIT: My way is essentially a rearrangement of LawrenceC's formula above.
 

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