Calculating Work Done: 25lb Force at 60 Degrees on Object - Find Distance Moved

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SUMMARY

The discussion focuses on calculating the distance moved by an object when a 25lb force is applied at an angle of 60 degrees, resulting in 125ft-lb of work done. The relevant equation for work is defined as the product of force, distance, and the cosine of the angle between the force and the direction of motion. Using the formula W = F * d * cos(θ), the distance can be calculated as d = W / (F * cos(θ)). Substituting the values, the distance moved is determined to be 10 feet.

PREREQUISITES
  • Understanding of the work-energy principle
  • Familiarity with trigonometric functions, specifically cosine
  • Basic knowledge of force and distance relationships
  • Ability to manipulate algebraic equations
NEXT STEPS
  • Review the work-energy theorem in physics
  • Study trigonometric identities and their applications in physics
  • Learn about vector components and their role in force calculations
  • Practice solving problems involving work done by forces at angles
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Students in physics, educators teaching mechanics, and anyone interested in understanding the principles of work and energy in applied physics scenarios.

jcamaross
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an applied force of 25lb acts on an object at an angle of 60 degrees with respect to the direction of its motion. if the work done by this force on the object is 125ft-lb,then what distance did it move while this work was done

a- 5ft
b- 10ft
c-15ft
d-20ft
e-25ft
 
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You'll need to try to work it out and show your attempt before we can assist. What is the definition of Work?
 
I am not sure how to start it off. I know work is the total amount of energy
 
Work done by an applied force is total change in energy, but that doesn't help here. There is a definition of work that relates force and distance. Can you find that equation somewhere in your notes/text/reference data/on-line?
 

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