Calculating Work Done in Moving Point Charge: Potential vs. Potential Energy

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SUMMARY

The discussion clarifies the calculation of work done in moving a point charge in electrostatics. The formula W=\int_{\mathbf{r_1}}^{\mathbf{r_2}} \mathbf{F} \cdot \mathbf{dr} is established as the correct method, yielding W=qV, where V represents the potential difference. The alternative approach using \mathbf{F}=-\nabla W is also valid but is framed within the context of potential energy, specifically in gravitational fields. Ultimately, the work done is defined by the integral of the force over the displacement.

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  • Understanding of electrostatics and electric potential
  • Familiarity with vector calculus, particularly line integrals
  • Knowledge of force fields and their representation
  • Concept of potential energy in physics
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This discussion is beneficial for physics students, educators, and professionals involved in electrostatics, particularly those focusing on electric potential and energy concepts.

latentcorpse
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In my electrostatics notes, when calculating the work done in moving a point charge from r1 to r2 we use

W=\int_{\mathbf{r_1}}^{\mathbf{r_2}} \mathbf{F} \cdot \mathbf{dr}
which ends up giving W=qV where V is the potential difference.

However in previous years we used \mathbf{F}=-\nabla W \Rightarrow W=-\int_{\mathbf{r_1}}^{\mathbf{r_2}} \mathbf{F} \cdot \mathbf{dr}

(this works if you consider W as potential energy (mgz) and then you get a force due to gravity of -mg in the z direction.

so which is correct and why?
 
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Work done by what? The work done by you in moving a particle from r1 to r2 in a force field F is always

- \int_{{r_1}}^{{r_2}} \mathbf{F} \cdot \mathbf{dr}
 

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