"Calculating Work Needed to Change Orbits

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Homework Help Overview

The discussion revolves around calculating the work required for a shuttle to deploy a satellite into a higher orbit, specifically from an initial orbit of 400 km to a final orbit of 600 km above the Earth's surface. The problem involves gravitational potential energy and kinetic energy considerations in the context of orbital mechanics.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss various methods to calculate work, including using kinetic energy and gravitational potential energy equations. There are attempts to clarify the correct distance measurement for gravitational calculations and questions about the consistency of energy values obtained through different approaches.

Discussion Status

Some participants have provided insights into the calculations and highlighted potential misunderstandings regarding the reference points for distance. There is an ongoing exploration of the relationship between kinetic energy and gravitational potential energy, with no clear consensus reached yet.

Contextual Notes

Participants are grappling with the implications of measuring distances from the center of mass and the assumptions about energy conservation in orbital mechanics. The original poster expresses confusion over differing results from various methods, indicating a need for clarification on the principles involved.

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Homework Statement



A shuttle orbiting the Earth at 400km deploys a satellite of mass 800kg into orbit a further 200km from earth. Calculate the work that must be done by the shuttle to deploy the sattelite.

Homework Equations



E_{k} = \frac{GMm}{2r}, U = -\frac{GMm}{r}

The Attempt at a Solution



I tried using W = \Delta E_{k} to solve the problem:

800GM\left(\frac{1}{2 \times 600000} - \frac{1}{2 \times 400000}\right)=-1.334 \times 10^{11} J

But the solutions gives 1.4 \times 10^9 J

Moreover, using the following method gives a different answer:

\int_{400000}^{600000} \frac{GM(800)}{r^2}dr=2.658 \times 10^{11} J

But I thought E_{tot} = E_{k} + U, so \Delta E_{k} = -\Delta U ??

Could someone tell me why my methods do not work and what the correct method is for dealing with this? Thankyou
 
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a case of mistaken Identity …

Hi Identity! :smile:
Identity said:
A shuttle orbiting the Earth at 400km deploys a satellite of mass 800kg into orbit a further 200km from earth. Calculate the work that must be done by the shuttle to deploy the sattelite.

Could someone tell me why my methods do not work

They do work …

but you need to measure r from … ? :wink:
 
Oh right I need to measure r from the centre of mass XD thanks tiny-tim

But

800GM\left(\frac{1}{2(6.4 \times 10^6 + 600000)} - \frac{1}{2(6.4 \times 10^6 + 400000)}\right)=-6.7 \times 10^8 J

which is still different!

Also, when the satellite moves from 400km to 600km, is the total energy of the satellite constant? If so, why do I get different answers when working with GPE as opposed to Kinetic energy?
 
Identity said:
800GM\left(\frac{1}{2(6.4 \times 10^6 + 600000)} - \frac{1}{2(6.4 \times 10^6 + 400000)}\right)=-6.7 \times 10^8 J

which is still different!

WIhtout seeing the details of your calculation, I can't check it …

but it would be a lot easier to use the formula 1/r - 1/(r + ∆) ~ ∆/r2 :wink:

anyway, going to bed now … :zzz:
 
lol I just plugged the whole calculation into my calculator...

Sorry I'm having some trouble understanding. Can you show me how you would do it?
 

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