Calculating Work on Incline: Solving for Gravitational Force Work

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SUMMARY

The discussion focuses on calculating the work done by gravitational force on a box being pushed up a frictionless incline. The box has a mass of 5 kg and is pushed a distance of 13 m at an incline of 34°. The correct formula for gravitational work is Wg = mgh, where h is the height calculated using h = d * sin(q). The participant initially calculated Wg as 358.1 J but later realized that the work done by gravity is negative, indicating that gravitational work opposes the motion.

PREREQUISITES
  • Understanding of gravitational force and work calculations
  • Knowledge of trigonometric functions, specifically sine
  • Familiarity with the concept of potential energy
  • Basic physics principles regarding forces on inclined planes
NEXT STEPS
  • Review the concept of work-energy principle in physics
  • Learn about calculating potential energy in inclined planes
  • Study the effects of friction on work done in similar scenarios
  • Explore advanced applications of trigonometry in physics problems
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This discussion is beneficial for physics students, educators, and anyone interested in understanding the dynamics of forces on inclined planes and the calculations of work done by gravitational forces.

mrnastytime
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Homework Statement


A horizontal force of magnitude F = 197 N is used to push a box of mass m = 5 kg from rest a distance d = 13 m up a frictionless incline with a slope q = 34°.


Homework Equations


How much work is done on the box by the gravitational force during this same displacement?


The Attempt at a Solution


Wg=mgh
Wg=5*9.81*7.3
i got 7.3 by using sin34=h/13
Wg=358.1 J
The answer i got is wrong according to the online hw. What am i missing? did i use the wrong formula?
 
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Maybe it would be negative?

Work by you is +, work by gravity is stored as potential = (-)?
 
wow, it is negative. thank you very much!
 

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