Calculating Work Output, Input, and Effort

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SUMMARY

The discussion focuses on calculating work output, work input, and effort applied in physics problems involving inclined planes and moving objects. For the first scenario, the work output is determined to be 960 J, while the work input is calculated as 24 J, leading to an effort of 1.5 N. In the second scenario, the work output for a 16,000 N car moving up a 15 m incline is 240,000 J, with the time taken calculated as 30 seconds, resulting in an engine power output of 8,000 W.

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  • Understanding of basic physics concepts such as work, power, and efficiency
  • Familiarity with formulas for calculating work output and input
  • Knowledge of inclined plane mechanics
  • Ability to perform unit conversions and basic algebra
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  • Learn about the relationship between work, energy, and power in physics
  • Explore the concept of efficiency in mechanical systems
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USEFUL FOR

This discussion is beneficial for physics students, educators, and engineers who are involved in mechanics and energy calculations, particularly in scenarios involving inclined planes and work-energy principles.

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First Question

'A worker is rolling a 480-N barrel up a 16-m ramp onto a platform 2.0 m above the floor. The efficiency = arrangement is 40%. What is the work output, work input, and effort applied to the barrel..

To find work output, you would just multiply the resistance force (480) by the distance of resistance (2.0) and get 960 right?

To find work input , you would use the given information: Efficiency = Wout / Winput, so 40% = 960 / x = 24 J right?

TO find effort applied, you would just setup Winput = E * De, 24 = X * 16 = 1.5 N right?


Second Question

"16,000 N car is moving up a hill at 12 m/s, hill = 360 m long and 15 m high.. What work does the car's engine do in getting to the top, how long does it take, and what power does the engine do?"

I believe the first part is asking for Woutput, so Woutput = 16,000 * 15 = 240,000 J right?

To find out how long it takes, do we just divide the distance the car has to travel by the velocity? (360 / 12), or am i completely wrong there?
 
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To find the power of the engine, you would just divide the work output by the time it took to get to the top (240,000 / 30 = 8,000 W right?)
 

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