Efficiency of Ramp: Solving Box Push Up Problem

In summary, the problem involves a 7.0 kg box being pushed up a ramp with a height of 6 m and a hypotenuse of 12 m in 3.25 s. A force of 40 N is required to push the box at a constant velocity. To find the efficiency of the ramp, the normal force of the box must be determined, which is 68.6 N. The efficiency is then calculated to be 58%.
  • #1
Zack K
166
6

Homework Statement


A 7.0 kg box is pushed up the ramp (height is 6 m and hypo is 12 m) in 3.25 s. If it requires a force of 40 N to push at a constant velocity, what is the efficiency of the ramp?

Homework Equations


Eff=(Wout/Win) x100
W= Fxd
F=ma

The Attempt at a Solution


The problem I have is that I don't know if 40.0 N is the force for Wout or Win. But I am guessing that it is Win since it's the minimum force need to push at a constant velocity. Then to get Wout you find the Normal force of the box which is 7 kg x 9.8= 68.6 N then you use W=68.6 x 12= 823 J. 480/823=58% efficient. But of course that's not right.
 
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  • #2
How much energy goes into the box pushing it up the ramp?
How much of that energy does the box finish up with?
 
  • #3
Zack K said:
Normal force of the box which is 7 kg x 9.8= 68.6 N
since it's a ramp, the normal force would not equal to the weight of object.
 
  • #4
So by definition the efficiency is eff=(how much energy you got out)/(how much energy you put in). In this problem, the 40N is the force you put in and the potential energy is the energy you get out. Hope that helps you
 

Related to Efficiency of Ramp: Solving Box Push Up Problem

1. What is the efficiency of a ramp in solving the box push up problem?

The efficiency of a ramp in solving the box push up problem depends on several factors such as the angle of the ramp, the weight of the box, and the coefficient of friction between the ramp and the surface. Generally, a steeper ramp with a lower coefficient of friction will result in a more efficient solution.

2. How is the efficiency of a ramp determined in solving the box push up problem?

The efficiency of a ramp is determined by calculating the mechanical advantage, which is the ratio of the output force (the weight of the box) to the input force (the force required to push the box up the ramp). The higher the mechanical advantage, the more efficient the ramp is in solving the box push up problem.

3. Can the efficiency of a ramp be improved for solving the box push up problem?

Yes, the efficiency of a ramp can be improved by reducing the coefficient of friction between the ramp and the surface, using a steeper angle for the ramp, and ensuring that the ramp is smooth and free of any obstacles.

4. Are there any limitations to the efficiency of a ramp in solving the box push up problem?

Yes, the efficiency of a ramp is limited by the angle at which it is placed. If the ramp is too steep, the box may slide down too quickly, making it difficult to control and push up. Additionally, the weight of the box and the coefficient of friction between the ramp and the surface can also impact the efficiency of the ramp.

5. How can the efficiency of a ramp be compared to other methods of solving the box push up problem?

The efficiency of a ramp can be compared to other methods by calculating the mechanical advantage of each method and comparing them. Other methods may include using a pulley system or using a lever to lift the box. The method with the highest mechanical advantage is considered the most efficient in solving the box push up problem.

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