The problem involves calculating the work done by a variable force defined by the function F(x) = 50(5 - √x) as an object is moved from 0 to 9 meters. Participants are exploring the correct evaluation of the integral to determine the work done.
The discussion is ongoing, with participants sharing their calculations and questioning the validity of the provided answer. There is a recognition of the need to verify the calculations and assumptions made regarding the force function.
Participants note that the force function may not always be positive, prompting further examination of its behavior over the interval of interest. There is also mention of the possibility that the provided answer may be incorrect.
physics79 said:Homework Statement
An object is moved from 0 to 9 meters with a force varying according to the function F(x)= 50(5-square root x). What is the work done.
Homework Equations
The Attempt at a Solution
I tried to take the integral and evaluate it from 0 to 9. I get 1350J no matter what I do, which is not correct. The correct answer is given as 1700 J. Any help?
ZxcvbnM2000 said:I will only say that F(x) is not always positive.
Steely Dan said:Yes, but it is positive over the spatial domain in question. Furthermore, since this is a conservative force, the work done from the starting point to the ending point will be independent of the path.
My calculation yields the same number as the OP's.