Calculating the work done from an equation for variable force

[giveortake]

Homework Statement

The force on a particle is directed along an x axis and given by F = F0(x/x0 - 1) where x is in meters and F is in Newtons. If F0 = 1.5 N and x0 = 4.9 m, find the work done by the force in moving the particle from x = 0 to x = 2x0 m.

Homework Equations

F = force, w = work, x = displacement
W=F*x
∫F(x)dx = W

The Attempt at a Solution

Integral from 0 to 9.8 of ( 1.5 * (( x / 4.9) - 1) ) = -7.35 J

 

[Andrew Mason]

Hi giveortake. Welcome to PF!

You should show us how you calculated your answer so we can see where you may have gone wrong.

It might be a good idea to do a graph of F(x). What shape is the graph? Where are the x and y intercepts? What does the area between the F(x) and the x-axis represent? The graphs shows two areas, one below and one above the x axis. What can you say about the two areas?

AM

 

[scottdave]

That's not what I got.
Show the intermediate step: Integral of [(x/a) - 1]dx. Where a is a constant. The 1.5 can be moved out of the integral and multiplied at the end.