The force on a particle is directed along an x axis and given by F = F0(x/x0 - 1) where x is in meters and F is in Newtons. If F0 = 1.5 N and x0 = 4.9 m, find the work done by the force in moving the particle from x = 0 to x = 2x0 m.
F = force, w = work, x = displacement
∫F(x)dx = W
The Attempt at a Solution
Integral from 0 to 9.8 of ( 1.5 * (( x / 4.9) - 1) ) = -7.35 J