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## Homework Statement

The force on a particle is directed along an

*x*axis and given by

*F*=

*F*0(

*x*/

*x*0 - 1) where

*x*is in meters and

*F*is in Newtons. If F0 = 1.5 N and x0 = 4.9 m, find the work done by the force in moving the particle from

*x*= 0 to

*x*= 2

*x*0 m.

## Homework Equations

F = force, w = work, x = displacement

W=F*x

∫F(x)dx = W

## The Attempt at a Solution

Integral from 0 to 9.8 of ( 1.5 * (( x / 4.9) - 1) ) = -7.35 J