the question is:
A 62 kg person in an elevator is moving up at a constant
speed of 4.0 m/s for 5.0 s. T / I C
(b) Calculate the work done by the normal force on the person.
(c) Calculate the work done by the force of gravity on the
(d) How would your answers change if the elevator were
moving down at 4.0 m/s for 5.0 s?
W= F x Δd
and i think
Δd= (vf + vi/2)Δt
The Attempt at a Solution
for b) i did Δd= (vf + vi/2)Δt and got displacement which is 10 m and then i did fn=fg since fnet is 0 which means that they have the same force. and for that i got 607.6 N
p.s the answer in the back is 12 kJ which i don't get?