Complex Kinematics and Dynamics

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Homework Help Overview

The problem involves two pucks on a table, where one puck is initially at rest and the other is moving towards it. The scenario includes forces acting on the pucks, including an applied force on one puck and friction between the surfaces. The objective is to determine how far the stationary puck travels before colliding with the moving puck.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss the decomposition of the applied force into its components and question the clarity of variable definitions. There are inquiries about the direction of the applied force and its implications on the motion of the pucks. Some participants suggest considering the interaction between the two pucks as they move towards each other.

Discussion Status

The discussion is ongoing, with participants providing feedback on the original poster's calculations and assumptions. There is a suggestion to analyze the motion of Puck B under the influence of friction and to compare the timing of the two pucks' movements.

Contextual Notes

There are indications of missing information, such as a clear definition of variables and a diagram to illustrate the setup. Participants express concern over the original poster's adherence to the problem template.

Vraj Patel
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Homework Statement


Two pucks (5 kg each) made of Teflon are on a long table, also made of Teflon. Puck A is sitting at
rest on the left end of the table. Puck B is 15 m away at the right hand end of the table, and is
travelling toward Puck A with an initial speed of 0.5 m/s. A person on the left waits 1.5 seconds and
then pushes Puck A forward from rest with a force of 20 N applied at an angle of 30° to the horizontal.
If that force is maintained at a steady rate for the entire question, how far will puck A travel before it
strikes puck B? (The coefficient of friction between the Teflon and Teflon is 0.04.

2. The attempt at a solution:

Puck A
Fax = 20NSin30
Fax = 10N

Fay = 20NCos30
Fay = 17.32N

Fg = mg
Fg = (5kg)(9.8m/s^2)
Fg = 49N


Fn = Fay + Fg
Fn =17.32N + 49N
Fn = 66.32

Ff = uFn
Ff = (0.04)(66.32N)
Ff = 2.65

Fnet = Fax - Ff
Fnet = 10N - 2.65
Fnet = 7.35N

a = Fnet/m
a = 7.35N/5kg
a = 1.47m/s^2

d = v1t + 1/2at^2
15-x = 1/2(1.47)(y-1.5)^24
x = -0.74y^2 + 2.22y +13.33

Puck B
Fg = mg
Fg = (5kg)(9.8m/s^2)
Fg = 49N

Ff = uFn
Ff = (0.04)(49N)
Ff = 1.96N


Since there is no applied force Fnet = -Ff

a = Fnet/m
a = -1.96/5kg
a = -0.39m/s^2

d = v1t + 1/2at^2
x = (0.5)(y) + 1/2(-0.39)(y)^2
-0.74y^2 + 2.22y +13.33 = 0.5 - 0.195y^2
0 = 0.545y^2 - 1.72y-13.33


I then put it in the quadratic formula and got:
y = 6.77s and y = -3.61s(omited)


Puck A Distance
d = v1t + 1/2at^2
d = (0m/s)(6.77s-1.5s) + 1/2(1.47m/s^2)(6.77-1.5s)^2
d = 20.41m(This answer doesn't make sense)
 
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Hi,

First thing that comes to mind is your decomposition of the 20 N in ##F_x## and ##F_y## ... :rolleyes:

Second thing I notice is that you deleted part 2 of the template -- not good !
Third is I miss a list of variable names. What is ##d## ? (and: are you sure that is what you think it is ? -- a drawing might help an awful lot here ! )
 
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Vraj Patel said:
an angle of 30° to the horizontal.
Pushing down or pushing up?
 
Let's assume pushing down :wink:
 
haruspex said:
Pushing down or pushing up?
pushing down
 
BvU said:
Hi,

First thing that comes to mind is your decomposition of the 20 N in ##F_x## and ##F_y## ... :rolleyes:

Second thing I notice is that you deleted part 2 of the template -- not good !
Third is I miss a list of variable names. What is ##d## ? (and: are you sure that is what you think it is ? -- a drawing might help an awful lot here ! )
d represents distance.
 
BvU said:
Hi,

First thing that comes to mind is your decomposition of the 20 N in ##F_x## and ##F_y## ... :rolleyes:

Second thing I notice is that you deleted part 2 of the template -- not good !
Third is I miss a list of variable names. What is ##d## ? (and: are you sure that is what you think it is ? -- a drawing might help an awful lot here ! )
I tried to upload a photo of my diagram but it wouldn't let me, but the pucks are heading toward each other.
 
Vraj Patel said:
d represents distance.
I know. How does your expression for ##d## deal with the fact that the pucks are moving towards each other (as opposed to: moving away from each other, or moving in the same direction) ?
 
Hint: Puck B has no external force affecting it other than friction. So why not find out how far it can coast before coming to rest, and how long it takes to come to rest? Is it less than or greater than the 1.5 s pause before puck A starts to move?
 

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